# Line slope calculator 8x+5y=58

**Straight line given by points A[1; 10] and B[6; 2]**

## Calculation:

**Slope-intercept form of line:**y = -1.6x+11.6

**Canonical form of the line equation:**8x+5y-58 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -8t+10 ; t ∈ R

**Slope:**m = -1.6

**Slope angle of line: φ =**-57°59'41″ = -1.0122 rad

**X intercept:**x

_{0}= 7.25

**Y intercept:**y

_{0}= q = 11.6

**Distance line from the origin:**d

_{0}= 6.148

**The length of the segment AB: |AB| =**9.434

**Vector: AB =**(5; -8)

**Normal vector: n =**(8; 5)

**Midpoint of the segment AB: M =**[3.5; 6]

**Perpendicular Bisector equation:**5x-8y+30.5 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (6; 2) ; |OB| = 6.3246**

**Scalar product OA .OB = 26**

**Angle ∠ AOB = 65°51'16″ = 1.1494 rad**